SOLUTION: The position of a projectile P shot directly upwards from the surface of the earth is a=117t-9.8t^2 What is the initial velocity of the projectile? Find the average velocity ov

Question 982883: The position of a projectile P shot directly upwards from the surface of the earth is a=117t-9.8t^2
What is the initial velocity of the projectile?
Find the average velocity over the interval from t=5 to t=10 seconds?
Find the instantaneous velocity at t=5 and t=10 secs?
Find the maximum height reach by the projectile?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The position of a projectile P shot directly upwards from the surface of the earth is a=117t-9.8t^2
What is the initial velocity of the projectile?
Ans: 117 units/sec
----------------------------
Find the average velocity over the interval from t=5 to t=10 seconds?
Ans: ave vel = [f(10)-f(5)]/[10-5] = [1170-980 -(585-245)]/[5] = -30 units/sec
--------------------------------------
Find the instantaneous velocity at t=5 and t=10 secs?
a'(x) = 117-19.6t
a'(5) = 117-19.6*5 = 19 units/sec
a'(10) = 117 - 196 = -79 units/sec
--------------------
Find the maximum height reach by the projectile?
Solve a'(t) = 0
117-19.6t = 0
t = 5.97
---
Ans:: a=117t-9.8t^2
a(5.97) = 349.21 units
---------------
Cheers,
Stan H.
Ans: f(5.97) =
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