SOLUTION: A point moves so that its displacement s is given by s=16+48t-t^3, when and where will it stop and reverse its direction of motion?
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Question 982544: A point moves so that its displacement s is given by s=16+48t-t^3, when and where will it stop and reverse its direction of motion?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A point moves so that its displacement s is given by s=16+48t-t^3, when and where will it stop and reverse its direction of motion?
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Assuming t >= 0
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s=16+48t-t^3
s'(t) = 48 - 3t^2 = 0
t^2 = 16
t = 4
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