SOLUTION: What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?
Algebra.Com
Question 970629: What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?
Answer by khai(18) (Show Source): You can put this solution on YOUR website!
r = 6
3th = 24
nth term = a(r)^(n-1) {a is the first term}
you have to find the first term first.....
24 = a(6)^(3-1)
24 = 36a
a= 2/3 {so this is the first term, now you can find nth term}
nth term = (2/3)(6)^(n-1)
RELATED QUESTIONS
An arithmetic sequence has 1st term 6 and common difference 624. A geometric sequence has (answered by stanbon)
An arithmetic sequence has initial term 6 and common difference 624. A geometric sequence (answered by scott8148)
A geometric sequence has a term of a4= –54 and a common ratio of r = 3. What is the rule... (answered by ewatrrr,Theo)
1. Find a formula for the nth term of the following sequence: 4, 12, 36, 108, 324, . . .... (answered by htmentor)
the third and sixth terms of a geometric sequence are-75 and -9375 respectively. Find the (answered by htmentor)
The fifth term of a geometric sequence is 15 and the eighth term is -15/8. Find the first (answered by mananth)
A sequence has a third term of 18, and a common ratio of 3.
What is the fifth term?
(answered by tommyt3rd)
a sequence of 6 numbers has 3 as its first term and 225 as its last term. the first four... (answered by richwmiller)
the third term of a geometric sequence is 4 and the sixth term is 32/27. find the nth... (answered by MathLover1)