SOLUTION: If the sum of the first 2n terms of 2, 5, 8, .... is equal to the sum of the first n terms of 57, 59, 61...., then n is equal to-

Algebra.Com
Question 965943: If the sum of the first 2n terms of 2, 5, 8, .... is equal to the sum of the first n terms of 57, 59, 61...., then n is equal to-

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
If the sum of the first 2n terms of 2, 5, 8, .... is equal to the sum of the first n terms of 57, 59, 61...., then n is equal to-




















;   
;    

The desired answer is n=11 terms.

n=0 is a comical solution.  It's really a solution, too,
because if you take twice the sum of zero terms of the first
sequence you would have zero, and if you took the sum of zero 
terms of the second sequence you would also have zero.  And 
it's quite true that zero equals zero!  :)

Edwin

RELATED QUESTIONS

the sum of the first n terms,Sn of a series is given by Sn=2n*2/(n*n)+1,then is the... (answered by Fombitz)
The sum of the first n terms of a series is 2n^2−n. Find the nth... (answered by ikleyn)
if the sum of first n terms of the series 5,9,13,17,....is 275 then find n. (answered by josgarithmetic)
list the first six terms of the sequence defined by bn=2*4*6......2n / 2^n for n is... (answered by lynnlo)
list the first six terms of the sequence defined by bn=2*4*6......2n / 2^n for n is... (answered by lynnlo)
1 , 8 , 18 ... in the sequence above , the first term is 1 and the sum of the first n... (answered by KMST)
If there are (2n+1) terms in an arithmetic series, prove that the ratio of the sum of odd (answered by richard1234)
Find the arithmetic sequence which has the sum of its n terms equal to 2n^2+3n Thank... (answered by ikleyn,math_tutor2020)
the sum of the first n terms of a series is 5n^2-2n. the r-1 term... (answered by ikleyn)