SOLUTION: The 1st,2nd and 3rd term of an arithmetic progression are 8-x,3x and 4x+1..find x

Algebra.Com
Question 965502: The 1st,2nd and 3rd term of an arithmetic progression are 8-x,3x and 4x+1..find x
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
The 1st,2nd and 3rd term of an arithmetic progression are 8-x,3x and 4x+1..find x
, 

  (8-x)+d = 3x, 3x+d = 4x+1
    8-x+d = 3x, -x+d = 1
    -4x+d = -8     d = 1+x

     -4x+d = -8 
 -4x+(1+x) = -8  
   -4x+1+x = -8
     -3x+1 = -8
       -3x = -9
         x = 3

d = 1+x = 1+(3) = 4

Checking:  
1st term = 8-x = 8-3 = 5
2nd term = 3x = 3(3) = 9
3rd term = 4x+1 = 4(3)+1 = 12+1 = 13

5,9,13 form an arithmetic sequence.

Edwin
RELATED QUESTIONS

The 1st,2nd and 3rd terms of an arithmetic progression are 8-x,3x and 4x+1 respectively... (answered by josgarithmetic)
The 3rd,5th and 8thterma of an Arithmetic progression are 3x+8,x+24 and x^3+15... (answered by josgarithmetic)
Three numbers form an arithmetic sequence. The first term minus the third term is 8. When (answered by htmentor)
if 5x-3, x+2 and 3x-11 form an arithmetic progression, find the first term and the 21st... (answered by ewatrrr)
Hello,can anyone help me with these series and sequences questions? I have a test on them (answered by stanbon)
In a geometrical progression the sum of the 2nd and the 3rd terms is 6 and the sum of the (answered by KMST)
The 2nd, 4th and 8th terms of an arithmetic progression are the three consecutive terms... (answered by mananth)
the 3rd term of a linear sequence is twice the 1st term and the 8th term of the sequence... (answered by ikleyn)
the 3rd term of a linear sequence is twice the 1st term and the 8th term of the sequence... (answered by ikleyn)