SOLUTION: Write the series in expanded form and find the sum. 5 ∑(4j-16) j=1 A. (4 ∙ 1 - 16) - (4 ∙ 2 - 16) - (4 ∙ 3 - 16) - (4 ∙ 4 - 16) - (4 &#872

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Question 960620: Write the series in expanded form and find the sum.
5
∑(4j-16)
j=1
A. (4 ∙ 1 - 16) - (4 ∙ 2 - 16) - (4 ∙ 3 - 16) - (4 ∙ 4 - 16) - (4 ∙ 5 - 16) = -20
B. (4 ∙ 1 - 16) + (4 ∙ 2 - 16) + (4 ∙ 3 - 16) + (4 ∙ 4 - 16) + (4 ∙ 5 - 16) = -20
C. (4 ∙ 1 16) + (4 ∙ 5 - 16) = -8
D. (4 ∙ 1 - 16) - (4 ∙ 5 - 16) = -16
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!


That means to substitute 1, 2, 3, 4, and 5 for j in (4j-16)
and add all these 5 values, so when you do that you get (b).

Edwin
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