We try to find a multiplier, m, and an adder, a 3.5m+a = 13 13m+a = 41.5 41.5m+a = 127 Removing the decimals by multiplying each through by 2 7m+2a = 26 26m+2a = 83 83m+2a = 254 Solve the first for 2a 2a = 26-7m Substitute in the second 26m+26-7m = 83 19m+26 = 83 19m = 57 m = 3 Substitute in 2a = 26-7m 2a = 26-7(3) 2a = 26-21 2a = 5 a = 2.5 See if those values satisfy 83m+2a = 254 83(3)+2(2.5) = 254 249 + 5 = 254 254 = 254 Yes they do! So substituting in 3.5m+a = 13 13m+a = 41.5 41.5m+a = 127 3.5(3)+2.5 = 10.5+2.5 = 13 13(3)+2.5 = 39+2.5 = 41.5 41.5(3)+2.5 = 124.5+2.5 = 127 Continuing the pattern: 127(3)+2.5 = 381+2.5 = 383.5 383.5(3)+2.5 = 1150.5+2.5 = 1153 1153(3)+2.5 = 3459+2.5 = 3461.5 Edwin