SOLUTION: IF 3(5/9) AND 40(1/2) ARE THE FIRST AND THE LAST TERMS RESPECTIVELY, OF A GEOMETRIC SEQUENCE, DETERMINE THE VALUE(S) OF THE FIFTH TERM IF THERE ARE SEVEN TERMS IN A SEQUENCE
Algebra.Com
Question 945179: IF 3(5/9) AND 40(1/2) ARE THE FIRST AND THE LAST TERMS RESPECTIVELY, OF A GEOMETRIC SEQUENCE, DETERMINE THE VALUE(S) OF THE FIFTH TERM IF THERE ARE SEVEN TERMS IN A SEQUENCE
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
is the first term of a geometric sequence with terms with common ratio .
is the last and seventh term of that same sequence.
.
So, .
Either way, the fifth term is
.
RELATED QUESTIONS
The first difference of a sequence is the arithmetic sequence 3, 5, 7, 9, 11, ...... Find (answered by greenestamps,ikleyn)
1) Find the explicit formula that produces the given sequence. 2,-6,18,-54,...
A.... (answered by Boreal)
write the first six terms of the sequence
2. an=(n+1)^3
4. an=n/n+3
write the next (answered by richard1234)
please help me. this is my last resort
1. Find the midpoint and... (answered by Fombitz)
2) Solve for x.
5x^2=-19x-12... (answered by Alan3354,ewatrrr)
The average of 9 is 40.the last three numbers are 30,32,34.find the average of the first... (answered by Boreal)
Please help me solve the following problems. I've tried to solve the problem but I don't (answered by venugopalramana)
Read the following lesson estimating square roots. Complete the table at the end and... (answered by KMST)
I've got this problem (see below). I've worked through problems 1b - 1d, but I am stuck... (answered by stanbon)