SOLUTION: PLEASE HELP ME I AM STUCK..... AN ARITHMETIC PROGRESSION SERIES HAS THE FIRST TERM 4 AND THE COMMON DIFFERENCE OF 3 .IF THE SUM OF ALL INTEGERS IS 375.HOW MANY TERMS ARE THERE? P

Question 936727: PLEASE HELP ME I AM STUCK.....
AN ARITHMETIC PROGRESSION SERIES HAS THE FIRST TERM 4 AND THE COMMON DIFFERENCE OF 3 .IF THE SUM OF ALL INTEGERS IS 375.HOW MANY TERMS ARE THERE?
PLEASE SOLVE IT AND EXPLAIN ME TOO
Found 2 solutions by Danielshinmath, MathTherapy:
Answer by Danielshinmath(31) (Show Source): You can put this solution on YOUR website!
The sum is 4n+3*(n-1)=4n+3n-3=375, where n is the amount of terms and 4 represents thee first term. The 3 represents the common difference.
if 4n+3n-3=375, that means 7n=375+3, which equals 7n=378. Then you get the answer n-378/7, or 54.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Stop writing in caps!!
Number of terms:
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