SOLUTION: 13. What is the missing term in the geometric sequence? 3/4, 1/2, 1/3, [?], 4/27, 8/81

Question 934571: 13. What is the missing term in the geometric sequence?
3/4, 1/2, 1/3, [?], 4/27, 8/81
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
A geometric series is one in which the RATIO of sequential terms is a CONSTANT.
To find the constant simply divide the second term of the sequence by the first term.
Given;
S = {3/4,1/2,1/3,?,4/27,8/81}
The constant is
(1) c = (1/2)/(3/4) or
(2) c = (1/2)*(4/3) or
(3) c = (1*4)/(2*3) or
(4) c = 4/6 or
(5) c = 2/3
Now check your sequence
S = {3/4, (2/3*(3/4)= 1/2, (2/3)*(1/2) = 1/3, ? = (2/3)*(1/3) = 2/9, (2/3)*(2/9) = 4/27, (2/3)*(4/27) = 8/81}
Answer: The missing (?) term is 2/9
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