SOLUTION: 1/3, 8/3, 27/3, 64/3, 125/3 identify the sequence

Question 931507: 1/3, 8/3, 27/3, 64/3, 125/3 identify the sequence
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the formula is:

An = A1 * n^3

A1 = 1/3 * 1^3 = 1/3 * 1 = 1/3
A2 = 1/3 * 2^3 = 1/3 * 8 = 8/3
A3 = 1/3 * 3^3 = 1/3 * 27 = 27/3
A4 = 1/3 * 4^3 = 1/3 * 64 = 64/3
A5 = 1/3 * 5^3 = 1/3 * 125 = 125/3

this is a geometric type sequence with a common ratio of n^3.

this is not a pure geometric sequence because the ratio changes each time.

in a pure geometric sequence the ratio remains the same.
an example of that would be An = 1/3 * 2^(n-1), where the common ratio is 2 and will always be 2.

with this sequence, you get An = A1 * n^3 where the common ratio is n^3 that keeps changing as you go from one n to another. when n = 2, the common ratio is 2^3, when n = 3, the common ratio is 3^3, etc. the only common thing about it is that n is constantly being cubed.

RELATED QUESTIONS
(-125/64)^-2/3 (answered by Alan3354)

(8/125) 1/3 (answered by KMST)

(-125/27)^-2/3 (answered by ewatrrr)

1Is the sequence geometric? If so, identify the common ratio. 1/4, 3/16, 9/64, 27/256, (answered by fcabanski)

27 1/3 (EXPONENT) - 125... (answered by Alan3354)

Write the equation for the following relation. Q = {(x, y): (2, 8), (3, 27), (4, 64),... (answered by Edwin McCravy)

Write the equation for the following relation.Q = {( x , y ): (2, 8), (3, 27), (4, 64),... (answered by MathLover1)

(-125)to -1/3 power over... (answered by stanbon)

(-125/64) to the -2/3... (answered by drk,richwmiller)