SOLUTION: Okay, so I'm having issues on how to find the nth term.. I know how to solve for the sum, which is what it wants me to do, but most of them dont give you the nth term. Please expl

Question 922031: Okay, so I'm having issues on how to find the nth term.. I know how to solve for the sum, which is what it wants me to do, but most of them dont give you the nth term.
Please explain what you did in each step? THANKS!!!!!
Calculate the sums of these series.
1.)
2.) this one scared me. I dont even think i know how to solve for the sum of this

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
All you ask for is n-th term, means you just examine to identify the sequence pattern. Q # 2 should be obvious.

Q # 1, is almost as simple.
3/10, 3/10^2, 3/10^3, 3/10^4, .....
The exponent on the 10 is the same as the index of the term. The first term is .

n-th Term is .
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Okay, so I'm having issues on how to find the nth term.. I know how to solve for the sum, which is what it wants me to do, but most of them dont give you the nth term.
Please explain what you did in each step? THANKS!!!!!
Calculate the sums of these series.
1.)
2.) this one scared me. I dont even think i know how to solve for the sum of this
1.

This is clearly a geometric sequence. This is seen when the 2^nd term is divided by the 1^st
term, and the 3^rd term is divided by the 2^nd term, and a common ratio (r) of is obtained
_____�_____________
____�_________
As seen, r, or the common ratio is:
, so n^th term is:

2.
This is clearly a geometric sequence. This is seen when the 2^nd term is divided by the 1^st
term, and the 3^rd term is divided by the 2^nd term, and a common ratio (r) of is obtained
________�_____
________�_____, or
As seen, r, or the common ratio is:
, so n^th term is:

You need to provide the NUMBER of terms, or the value of the last term in order for the SUM of each GP to be calculated.
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