SOLUTION: what is the nth term of the sequence 4/3,5/9,6/27,7/81

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Question 901879: what is the nth term of the sequence 4/3,5/9,6/27,7/81
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
The numerators go up by 1
it is an arithmetic progression
an = a + (n - 1)d
An = 4 + 1(n - 1)
The denominators go up by 3 times
It is a geometric progression
Tn = t * r^(n - 1)
Tn = 3 * 3^(n - 1)
(3+n)/(3*3^(n -1))
%283%2Bn%29%2F%283%2A3%5E%28n+-1%29%29