SOLUTION: what is the half life of a compound that decays at the formula y=ae^-0.0736t
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Question 888215: what is the half life of a compound that decays at the formula y=ae^-0.0736t
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Plug in y = a/2 and solve for t
y = a*e^(-0.0736t)
a/2 = a*e^(-0.0736t)
1/2 = e^(-0.0736t)
ln(1/2) = ln(e^(-0.0736t))
ln(1/2) = -0.0736t*ln(e)
ln(1/2) = -0.0736t*1
ln(1/2) = -0.0736t
ln(1/2)/(-0.0736) = t
9.41776060543403 = t
t = 9.41776060543403
The halflife is approximately 9.41776060543403 (use whatever units are part of the problem)
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