SOLUTION: What is the 17th term in the arithmetic sequence in which a^6 is 101 and a^9 is 83?
Algebra.Com
Question 877253: What is the 17th term in the arithmetic sequence in which a^6 is 101 and a^9 is 83?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
an = a + (n - 1)
101 = a + 5d,
83= a + 8d,
a17 = a + 16d
a17=131-6*(16)
a17=131-96
a17=35
a = 131, d = -6, t = 35
RELATED QUESTIONS
What is the 17th term in the arithmetic sequence in which a-sub-6 is 101 and a-sub-9 is... (answered by Edwin McCravy)
1) Use the explicit formula an=(-1)^n(13n-6), to find the first five terms of the... (answered by ikleyn)
1) Find the explicit formula that produces the given sequence. 2,-6,18,-54,...
A.... (answered by Boreal)
What is the sum of a 30–term arithmetic sequence where the first term is 73 and the last... (answered by jim_thompson5910)
the sum of the second and sixth terms of an arithmetic sequence is 4. the third term is... (answered by Fombitz)
The 13th term of a sequence is 8, and the 17th term is 8. What is the 25th term?
A:4... (answered by ikleyn)
The 17th term of an arithmetic progression is 81 and the 33th term is 145. Find a and d
(answered by plover)
Could I please get help with the following problem:
Find a general formula for the... (answered by nerdybill)
What is the twenty-ninth term of arithmetic sequence with a1=13 and d=-5/2?
A)-62... (answered by richwmiller)