SOLUTION: A geometric sequence has a1 = 16 and r = \sqrt{2}2, what is the sum of the first 21 terms?
Algebra.Com
Question 872386: A geometric sequence has a1 = 16 and r = \sqrt{2}2, what is the sum of the first 21 terms?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
What is "r = \sqrt{2}2," ?
RELATED QUESTIONS
Sum of the first 6 terms of a geometric progression equals to 63.
Sum of the even terms (answered by Boreal)
what is the sum of the first five terms of the geometric sequence in which a1=10 and... (answered by richwmiller)
What is the sum of the first five terms of a geometric series with a1=10 and... (answered by jim_thompson5910)
The sum of a finite geometric sequence for n terms with common ratio r and initial term... (answered by solver91311,ewatrrr,richard1234)
A geometric sequence has a1=36 and r=0.5. What is the 15th term of the sequence
(answered by fractalier)
1. Find a formula for the nth term of the following sequence: 4, 12, 36, 108, 324, . . .... (answered by htmentor)
The first 6 terms of the geometric sequence where r=4 and... (answered by Fombitz)
Give the first four terms of the geometric sequence for which a1=7 and... (answered by josgarithmetic)
(144,108,81,60.75,...)
Is the sequence arithmetic, geometric, or neither?
-I said... (answered by josgarithmetic,jim_thompson5910)