SOLUTION: The sum of first 12 terms of an A.P. is 28 and the sum of its first 28 terms is 12 ; find the sum of its first 40 terms.ans is -40..but how it solve??plz help...

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Question 867959: The sum of first 12 terms of an A.P. is 28 and the sum of its first 28 terms is 12 ; find the sum of its first 40 terms.ans is
-40..but how it solve??plz help...

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The sum of first 12 terms of an A.P. is 28 and the sum of its first 28 terms is 12 ; find the sum of its first 40 terms.ans is
-40..but how it solve??plz help...

With , and n = 12, the sum of an A.P. formula: becomes:




---------- Multiplying by LCD, 3
With , and n = 28, the sum of an A.P. formula: becomes:




---------- Multiplying by LCD, 7
--------- eq (i)
-------- eq (ii)
------- Multiplying eq (i) by 7 ------ eq (iii)
---- Multiplying eq (ii) by – 3 ----- eq (iv)
- 336d = 80 ---------- Adding eqs (iv) & (iii)
d, or common difference = , or

------- Substituting for d in eq (i)


------ Multiplying by LCD, 7


, or





Sum of the 1st 40 terms, or , or
You can do the check!!
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