SOLUTION: 3. A ball is dropped vertically from a height of 50 meters. After each bounce, the ball reaches a maximum height equal to 80 percent of the maximum height of the previous bounce.

Question 867307: 3. A ball is dropped vertically from a height of 50 meters. After each bounce, the ball reaches a maximum height equal to 80 percent of the maximum height of the previous bounce.
a.) Write the first three terms of the sequence. Explain how you know what they are.
b.) Find the height to the nearest tenth of a meter of the ball after the tenth bounce. Show and explain your work.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Tn = t * r^(n - 1)
Tn = 50 * .8^(n - 1)
T1= 50
T2= 40
T3= 32
T4= 25.6
T5= 20.48
T6= 16.384
T7= 13.1072
T8= 10.48576
T9= 8.388608
T10= 6.7108864
T11= 5.36870912

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