SOLUTION: In a geometric sequence, find the first five terms when An=(2)^n-1, starting with n=1. I would think this is (2)^1-1 which would be (2)^0=0, next would be (2)^2-1 =2, next would b

Question 860167: In a geometric sequence, find the first five terms when An=(2)^n-1, starting with n=1. I would think this is (2)^1-1 which would be (2)^0=0, next would be (2)^2-1 =2, next would be (2)^3-1=4, (2)^4-1=6, and (2)^5-1=8. However this answer of (0,2,4,6,8) is not a choice I have. Can someone help me understand if I am doing something wrong?

Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Using An=(2)^n-1 to determine the first 5 terms
2^0 2^1 2^2 2^3 2^4
1 2 4 8 16
therefore the sequence is 1, 2, 4, 8, 16
note that anything raised to the 0 power is 1

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