Parallel algebra question. X = 1, 2, 3, 4, 8, 10 Y = 2, 3, 5, 7, ?, ? It looks like the Y's are just the prime numbers. So the Y's go Y = 2, 3, 5, 7, 11, 13 That's really all you wanted. But maybe you're curious about the X's ----------------------------------- It looks like the X's follow this sequence 1,2,3,4,8,10,12,14,28,31,34,37,... Starting with 1, Count the first four by 1's. 1,2,3,4 Double the last of these, getting 8 Starting with 8 Count the second four by 2's, 8,10,12,14 Double the last of these, getting 28 Starting with 28 Count the third four by 3's, 28,31,34,37 Double the last of these, getting 74. etc. But there are probably other deducible patterns that work too. Edwin