SOLUTION: For part (a), find the sum of the first n terms of the geometric series. 60. 1 + 4 + 16 + 64 + . . . a. n = 14

SOLUTION: For part (a), find the sum of the first n terms of the geometric series. 60. 1 + 4 + 16 + 64 + . . . a. n = 14

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Question 853476: For part (a), find the sum of the first n terms of the geometric
series.
60. 1 + 4 + 16 + 64 + . . .
a. n = 14
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
S=t*(1 - r^n)/(1 - r)
S=1*(1 - 4^14)/(1 - 4)

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