SOLUTION: The first two terms of a geometric sequence and an arithmetic sequence are the same. The first term is 12. The sum of the first three terms of the geometric sequence is 3 more than

Algebra.Com
Question 840912: The first two terms of a geometric sequence and an arithmetic sequence are the same. The first term is 12. The sum of the first three terms of the geometric sequence is 3 more than the sum of the first three terms of the arithmetic sequence. Determine TWO possible values for the common ratio, r, of the geometric sequence
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
The first two terms of a geometric sequence and an arithmetic sequence are the same. The first term is 12. The sum of the first three terms of the geometric sequence is 3 more than the sum of the first three terms of the arithmetic sequence. Determine TWO possible values for the common ratio, r, of the geometric sequence
Geometric sequence = a,ar,arē,__,__,...

Arithmetic sequence= a,a+d,a+2d,__,__,...
The first two terms of a geometric sequence and an arithmetic sequence are the same.
a = a, ar = a+d

The first term is 12. 

a = 12,  12r = 12+d
The sum of the first three terms of the geometric sequence is 3 more than the sum of the first three terms of the arithmetic sequence.
   (a)+(ar)+(arē) = (a)+(a+d)+(a+2d)+3
(12)+(12r)+(12rē) = (12)+(12+d)+(12+2d)+3
      12+12r+12rē = 12+12+d+12+2d+3
      12+12r+12rē = 39+3d
         12r+12rē = 27+3d

Every term can be divided by 3

           4r+4rē = 9+d

So we have this system of two equations and 2 unknowns:

     12r = 12+d, 4r+4rē = 9+d

Solve the first for d:

         12r = 12+d     
      12r-12 = d

Substitute in

      4r+4rē = 9+d
      4r+4rē = 9+(12r-12)
      4r+4rē = 9+12r-12
      4r+4rē = 12r-3
    4rē-8r+3 = 0
(2r-1)(2r-3) = 0
   2r-1=0;  2r-3=0
     2r=1;    2r=3
      r=;    r=

Those are the two values.

---------------------------------------

To check we must find d

Using r = 

 12r-12 = d
12-12 = d
   6-12 = d
     -6 = d

Arithmetic sequence:  12, 6, 0, ...
Geometric sequence:   12, 6, 3, ...

Sum of 1st three terms of arithmetic sequence = 12+6+0 = 18
Sum of 1st three terms of geometric sequence  = 12+6+3 = 21
21 is 3 more than 18
That checks.

Using r = 

 12r-12 = d
12-12 = d
  18-12 = d
      6 = d

Arithmetic sequence:  12, 18, 24, ...
Geometric sequence:   12, 18, 27, ...

Sum of 1st three terms of arithmetic sequence = 12+18+24 = 54
Sum of 1st three terms of geometric sequence  = 12+18+27 = 57
57 is 3 more than 54
That checks, too.  So it's correct

Edwin

RELATED QUESTIONS

Three numbers form an arithmetic sequence. The first term minus the third term is 8. When (answered by htmentor)
2;x;y are the first 3 terms of an arithmetic sequence . If each term is decreased by 1,... (answered by richwmiller)
The first,third and eight term of an arithmetic sequence form the first three terms of a... (answered by richwmiller)
The first,third and eight term of an arithmetic sequence form the first three terms of a... (answered by richwmiller)
The sum of the first n terms of an arithmetic sequence is (2n^2)-n. Find the general term (answered by MathLover1)
The sum of the terms of an infinite geometric sequence is 18 and the sum of the first two (answered by reviewermath)
When the terms of a Geometric Progression(G.P) with common ratio r=2 is added to the... (answered by greenestamps,jim_thompson5910)
the third term of an arithmetic sequence is 9. The sum of the next two terms is -18. Find (answered by richwmiller)
An arithmetic sequence of 15 terms has a sum of 3060. The common difference and each... (answered by greenestamps)