They all have either exactly 2 or all 3 digits the same. There are 9 3-digit number with all 3 digits the same, 111,222,...999. The 3-digit numbers with exactly 2 digits the same are all of the form ABA, AAB, or ABB. (For example 575, 557, or 577) Therefore, we can choose the form in 3 ways. For each of those forms the A can be chosen 9 ways (A can't be 0). Then B can be chosen 9 ways (B can't be the same digit as A, but B can be 0) Answer: 9+3 = 9+243 = 252 possible 3-digit numbers with at least 2 digits the same. Edwin