SOLUTION: 1. Suppose each of two shoe boxes contains a mixture of black-and-white marbles. One of the two boxes is to be chosen at random and a marble chosen at random from that box. Let A=
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Question 838980: 1. Suppose each of two shoe boxes contains a mixture of black-and-white marbles. One of the two boxes is to be chosen at random and a marble chosen at random from that box. Let A= the event that box 1 is selected; Let B+ the even that box 2 is selected; C= the event that a black marble is drawn; D= the event that a white marble is drawn.
a. suppose box 1 contains 12 black and 8 white marbles, and box 2 contains 15 black and 10 white marbles. Show that A and D are independent.
b. suppose box 1 contains 8 black marbles and 2 white marbles, and box 2 contains 5 black and 5 white marbles. Find the probability that if a white marble was drawn, it came from Box 1.
c. suppose you have 100 marbles (50 back and 50 white) and are allowed to distribute them between the two boxes anyway you want. How should you do this so as to maximize the probability of that a black marble will be drawn?
If someone could help me out that would be great.
Thanks!
Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!
Use Bayes theorem for Conditional Probability. Cheers!
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