The series is





Let A(n) =  and B(n) = 

Then we seek to find A(n) + 3·B(n) 

We find summation A(n)

By the method of partial fractions:

 = 

A(n) = 


Now we find B(n):

Also by the method of partial fractions:



, so

B(n) = 



(Since that last sum is A(n) or 



And since  = 

B(n) = 

So:

A(n)+3B(n)

Getting LCDs, combining terms and factoring, the sum becomes:



Edwin