SOLUTION: Calculation of the following: 1+2+3+4....+97+98+99+100 I tried an arithmetic sequence a=1(100-1)1 but it wont work.

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Question 826123: Calculation of the following:
1+2+3+4....+97+98+99+100
I tried an arithmetic sequence a=1(100-1)1 but it wont work.
Found 3 solutions by richwmiller, stanbon, MathTherapy:
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
100+50 +
1+99+2+98
4900+150=5050
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Calculation of the following:
1+2+3+4....+97+98+99+100
-------
s(n) = (n/2)(a + L)
----
s(100) = (100/2)(1+100)
----
s(100) = 50*101
-----
s(100) = 5050
================
Cheers,
Stan H.
----------------
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Calculation of the following:
1+2+3+4....+97+98+99+100
I tried an arithmetic sequence a=1(100-1)1 but it wont work. 


I take it you're trying to sum all integers from 1 to 100, inclusive, with a difference of 1 between terms.



Number of terms (n)in the series: 100



The formula for the sum of a sequence, when the 1st and last terms, the number of terms in the series,

as well as the common difference, are known is: 

Sum of sequence:                

Number of terms in series:      

First term in sequence, or :  

Last term in sequence, or :   



 now becomes: 





The sum of the 1st 100 POSITIVE INTEGERS is:  50(101), or 

You can do the check!! 



Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.

Further help is available, online or in-person, for a fee, obviously. 



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