SOLUTION: divide 105 into two parts such that one half of the first exceeds one fifth of the second by 35. find the number. please help me to solve this.

Algebra.Com
Question 825149: divide 105 into two parts such that one half of the first exceeds one fifth of the second by 35. find the number.

please help me to solve this.

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
x+y=105,
x/2=y/5+35
x = 80, y = 25

RELATED QUESTIONS

divide 95 into two parts such that one half of the first part exceeds one fifth of second (answered by stanbon)
divide 105in to two parts in which the first half part exceeds the one fifth of the... (answered by stanbon)
Divide 56 Into Two Parts Such That Three Times The First Parts Exceeds One Third Of The... (answered by lynnlo)
Divide 56 into two parts such that three times the first part exceeds one third of the... (answered by Boreal)
Divide 56 into two parts such that three times the first part exceeds one third of the... (answered by josgarithmetic)
Divide 56 into two parts such that three times the first part exceeds one third of the... (answered by math_helper)
Divide 56 into two equal parts such that 3 times the first part exceeds one third of the... (answered by ikleyn)
Divide 20 into two parts such that three times the square of one part exceeds the other... (answered by amarjeeth123)
Divide rs.350 into two parts such that the half of greater part exceeds the smaller part... (answered by Cromlix)