SOLUTION: Sequence: 1, 9, 25, 49, ... a) Find a6 b) Find an each number is the square of each odd consecutive number (1, 3, 5, 7, ...) and a6 = 121 but there has to be algebraic work

Question 825128: Sequence: 1, 9, 25, 49, ...
a) Find a6
b) Find an
each number is the square of each odd consecutive number (1, 3, 5, 7, ...) and a6 = 121 but there has to be algebraic work to show how a6 = 121
my teacher's really vague about work but my guess she wants a rule that you can use to solve this sequence. I can't spot the common difference/ratio.
all i have so far is a6=5d+1 or a6=r^5
i know how to determine if this is an arithmetic or geometric sequence but this ones confusing me :(
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Sequence: 1, 9, 25, 49, ...
a) Find a6
b) Find an
each number is the square of each odd consecutive number (1, 3, 5, 7, ...) and a6 = 121 but there has to be algebraic work to show how a6 = 121
my teacher's really vague about work but my guess she wants a rule that you can use to solve this sequence. I can't spot the common difference/ratio.
all i have so far is a6=5d+1 or a6=r^5
i know how to determine if this is an arithmetic or geometric sequence but this ones confusing me :(
--------------
a6 = 121
an = (2n-1)^2

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