SOLUTION: Sequencing integers: 4,16,37,58,89,145,42,20,4,16 How is each term obtained from the term before it?

Algebra ->  Sequences-and-series -> SOLUTION: Sequencing integers: 4,16,37,58,89,145,42,20,4,16 How is each term obtained from the term before it?       Log On


   

Question 814195: Sequencing integers: 4,16,37,58,89,145,42,20,4,16
How is each term obtained from the term before it?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Take sum of squares of digits of previous term.
1 6 then 37
1 +36=37
3 7
9+49=58