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put this solution on YOUR website!QUESTION:
The difference of two numbers is 33. The second is 7 less than 3 times the first. What are the two numbers?
ANSWER:
Let us assume that one number is x.
Three times of x can be written as 3x.
7 less than 3 times the first can be written as 3x - 7.
Then we can take the other number as 3x - 7.
It is given that their difference is 33.
So we can write, first number -second number = 33
That is x - (3x-7) = 33
==> x - 3x + 7 = 33 ( remove the parenthesis by multiplying each term inside it with -1.)
==> -2x + 7 = 33. ( x - 3x = -2x)
Subtract 7 from both sides of the equation. Then we have,
-2x + 7 - 7 = 33 - 7
==> -2x = 26
Now divide both sides of the equation by -2.
==> -2x/-2 = 26/-2
==> x = -13.
So the first number is -13.
We have second number = 3x - 7
= 3(-13) - 7
= -39 - 7
= -46.
So the numbers are -13 and -46.
To check the answer....find the difference of these numbers.
That is -13 - (-46) = -13 + 46 = 33.That is our answer is correct.
Hope you understood.
Regards.
Praseena.
