SOLUTION: Given the sequence of first differences: 8, 10, 12, 14 find the first six terms of the original sequence if the sum of the third and fourth terms of the original sequence is 40
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Question 790518: Given the sequence of first differences: 8, 10, 12, 14 find the first six terms of the original sequence if the sum of the third and fourth terms of the original sequence is 40
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The difference between 
and 
is 12 from the sequence of first differences, and the sum of and is given as 40. That is a 2X2 system. Solve the 2X2 system for and , then the rest should just fall into place.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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