SOLUTION: 12^10, (12^10 + 12^10), (12^10 + 12^10 + 12^10), ... In the sequence above, the first term is 12^10 more than the preceding term. Which term in the sequence is equal to 12^12?

Algebra.Com
Question 788113: 12^10, (12^10 + 12^10), (12^10 + 12^10 + 12^10), ...
In the sequence above, the first term is 12^10 more than the preceding term. Which term in the sequence is equal to 12^12?
A. The 3rd term
B. The 12th term
C. The 24th term
D. The 120th term
E. The 144th term

Answer by KMST(5328)   (Show Source): You can put this solution on YOUR website!
In that sequence, the first term is , and each term is more than the preceding term.
= first term
= common difference
= nth term





-->

RELATED QUESTIONS

Find the nth term of a sequence whose first several terms are given. 9/10, 10/11,... (answered by flame8855)
The 10 in term of an Ap is_27and in term is_12 what is the 18 in... (answered by greenestamps)
The 10 in term of an Ap is_27and in term is_12 what is the 18 in... (answered by greenestamps)
what is... (answered by killer6678)
3•(12•10)=3•(10•12) =(3•10)•12... (answered by josgarithmetic)
(20+10)10=(x+12)12 (answered by Fombitz)
12^-3 * 12^10 *... (answered by Alan3354)
Find the term that has x^10 in the expansion of... (answered by robertb)
write an equation describing the rules for each sequence. Then give the 100th term for... (answered by stanbon)