SOLUTION: My question was about arithmetic series. Sn = -126, t1= -1, and tn = -20 How do I determine n?

Question 782030: My question was about arithmetic series. Sn = -126, t1= -1, and tn = -20
How do I determine n?

Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
My question was about arithmetic series. Sn = -126, t1= -1, and tn = -20
How do I determine n?
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Using S(n) = -126 you get: -126 = (n/2)(-1-20)
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-252 = -21n
n = 12
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Cheers
Stan H.
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Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Sn = -126, t1= -1, and tn = -20
How do I determine n?
tn = a+(n-1)d
-20 =-1+(n-1)d
-19=(n-1)d
Sn= n/2[2a+(n-1)d]
-126=n/2[2(-1)+(n-1)d]
substitute (n-1)d =-19
-252=n[-2-19)]
-252=n[-21]
-252/-21=n
n=22
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