1,4,7,10,13 To get the 2nd term 4, you add 3 to the 1st term 1 time To get the 3rd term 7, you add 3 to the 1st term 2 times To get the 4th term 10, you add 3 to the 1st term 3 times. To get the 5th term 13, you add 3 to the 1st term 4 times. To get the nth term an, you add 3 to the 1st term (n-1) times. an = a1 + (n-1)·d Substitute a1 = first term = 1 and d = 3 (the common difference between any term and the one before it. an = 1 + (n-1)·3 = 1 + 3(n-1) = 1 + 3n - 3 = 3n-2. an = 3n-2 Substitute n=20: a20 = 3(20)-2 = 60-2 = 58. Checking: 1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52,55,58 Edwin