given the sequence: 5,8,11,......,101 find the number of terms a1 = first term = 5 d = a2 - a1 = 8 - 5 = 3 d = a3 - a2 = 11 - 8 = 3 Since those are the same, the sequence is arithmetic. an = a1 + (n-1)d 101 = 5 + (n - 1)(3) 101 = 5 + 3(n - 1) 101 = 5 + 3n - 3 101 = 2 + 3n 99 = 3n 33 = n Checking: 5,8,11,14,17,20,23,26,29,32,35, 38,41,44,47,50,53,56,59,62,65,68, 71,74,77,80,83,86,89,92,95,98,101 Count them. There are 33 of them. Edwin