SOLUTION: ax3+bx2+cx+d=0,where a=0,

SOLUTION: ax3+bx2+cx+d=0,where a=0,

Algebra.Com

Question 759214: ax3+bx2+cx+d=0,where a=0,
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
please repost with a clear and complete question :)
RELATED QUESTIONS
A quadratic function is of the form a. y = ax3 + bx2 + cx + d b. y = ax2 + bx + (answered by ewatrrr)

# If x2-x+1=0 is a factor of ax3+bx2+cx+d=0 then a) d - a = b - 2c b) a - d = b + 2c... (answered by MathLover1)

Find a polynomial of the form f(x)=ax3+bx2+cx+d such that f(0)=2, f(2)=−2,... (answered by Boreal)

Find ax3 + bx2+ cx + d so that a,b,c, and d are integers. a/c =b/d = 4 and a/b =7/5.... (answered by jsmallt9)

{{{ax^3+bx^2+cx+d=0}}} (answered by ikleyn)

cx-b=cx+d (answered by Fombitz)

1) The line y= 3x + 4 is a tangent to the curve y=ax3+bx2 +2x+7 at the point (1,7) 1a.) (answered by MathLover1)

1) The line y= 3x + 4 is a tangent to the curve y=ax3+bx2 +2x+7 at the point (1,7) 1a.) (answered by MathLover1)

The figure shows the graphs of f(x) = x3 and g(x) = ax3. What can you conclude about the (answered by MathLover1)