SOLUTION: each stroke of a vacuum pump removes one third of the air ramianing in a container. wut percent of the original quanity of the air ramains in the container after 10 strokes, to the

Question 75801: each stroke of a vacuum pump removes one third of the air ramianing in a container. wut percent of the original quanity of the air ramains in the container after 10 strokes, to the nearest percentage?
we r workin with geometric sequence
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
SINCE EACH STROKE REMOVES 1/3 OF THE AIR THEN THE REMAINING AIR IS 2/3 WHICH IS AGAIN REDUCED BY 1/3 WITH EACH SUCCESSIVE STROBE LEAVING 2/3 OF THE REMAING AIR, ETC. SO AFTER 10 STROKES WE HAVE LEFT:
2/3*2/3*2/3*2/3*2/3*2/3*2/3*2/3*2/3*2/3=1,024/59,049=.0173415=1.7% OF THE AIR IS LEFT.
OR
(2/3)^10=.0173415=1.7%
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