SOLUTION: The product of two consecutive integers is 9 less than 9 times their sum. Find the integers. I would like to know how to do this problem
Algebra.Com
Question 751306: The product of two consecutive integers is 9 less than 9 times their sum. Find the integers. I would like to know how to do this problem
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The product of two consecutive integers is 9 less than 9 times their sum. Find the integers.
----------------
1st: x
2nd: x+1
------
Equation:
x(x+1) = 9(x + x+1)+9
-------
x^2 + x = 9(2x+1)+9
x^2 + x = 18x+18
------------
x^2 -17x -18 = 0
(x-18)(x+1) = 0
Positive solution:
x = 18
x+1 = 19
=============
Cheers,
Stan H.
RELATED QUESTIONS
The product of two consecutive integers is 9 less than 9 times their sum. Find the... (answered by solver91311)
The product of two consecutive integers is 9 less than 9 times their sum. Find the... (answered by checkley71)
The product of two consecutive integers is 9 less than 9 times their sum. Find the... (answered by Jk22)
the product of two consecutive integers is 9 less than 9 times their sum. find the... (answered by stanbon)
The product of two consecutive even integers is 18 less than 9 times their sum. Find the... (answered by dfrazzetto)
The product of two consecutive odd integers is 57 less than 9 times their sum. Find the... (answered by CubeyThePenguin,josgarithmetic)
The product of two consecutive even integers is 46 less than 9 times their... (answered by CubeyThePenguin)
Product of two consecutive integers is 6 less than 6 times their sum. Find the... (answered by RAY100)
Hello,
Could you please help me with this problem about integers? I have no clue on how... (answered by josmiceli)