SOLUTION: When given t2=4 and t5=22, how would you find t23 in a arithmetic sequence?
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Question 745180: When given t2=4 and t5=22, how would you find t23 in a arithmetic sequence?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
t2 = 4
t3 = t2+d
t3 = 4+d
t4 = t3 + d
t4 = (4+d) + d
t4 = 4 + 2d
t5 = t4 + d
t5 = (4+2d) + d
t5 = 4 + 3d
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t5 = 4 + 3d
22 = 4 + 3d
22 - 4 = 3d
18 = 3d
3d = 18
d = 18/3
d = 6
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t1 = t2 - d
t1 = 4 - 6
t1 = -2
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tn = t1 + d(n-1)
tn = -2 + 6(n-1)
tn = -2 + 6n-6
tn = 6n - 8
------------------
tn = 6n - 8
t23 = 6*23 - 8
t23 = 130
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