SOLUTION: The infinite geometric sequence which begins: (2^300),(2^298),(2^296),(2^294)... contains only ONE odd integer. This odd integer is the nth term of the sequence. What is the

Question 73595: The infinite geometric sequence which begins:
(2^300),(2^298),(2^296),(2^294)...
contains only ONE odd integer. This odd integer is the nth term of the sequence. What is the value of n?
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I figured out the equation for the sequence, but don't know how to find out the odd integer.
equation: (2^302-2n)
Answer by joyofmath(189) (Show Source): You can put this solution on YOUR website!
is always going to be even except when in which case .
So, when is ? That'd be when or .
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