Hmm. That's close to the increasing sequence of cubes, which is this sequence: 1,8,27,64,125,... Let's form a sequence of differences from the sequence of cubes: 1-0,8-1,27-2,64-3,125-4, Aha, so 1 = 1³ - 0 7 = 2³ - 1 25 = 3³ - 2 61 = 4³ - 3 121 = 5³ - 4 So the next one is 6³-5 = 211 The nth term is n³-(n-1) or an = n³-n+1 Edwin