SOLUTION: U r asked by ur elderly neighbour to lay a stone path frm the back door of her house to the bird feeder 44 units across her backyard.each unit is 500mm.she purchased 15 crircular s

Question 715354: U r asked by ur elderly neighbour to lay a stone path frm the back door of her house to the bird feeder 44 units across her backyard.each unit is 500mm.she purchased 15 crircular stones,each 1 unit wide in diameter,nd wud lyk u to place them equally spaced across the backyard with the last stone touching the feeder.the distance frm the houset to the first stone is up to you,so you may make it different to the spacing betwe to u.how far apart would u lay the stones to use all the 15?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
To make all spaces the same, the space before each stone plus the diameter of the stone would have to be

That is about .
Using a unit spacing between stones, each 1-unit wide stone plus the extra 2 units before it would take up units of space.
So stones plus the spaces before each one would take up
units.
That leaves units of space for the first stone plus the space between that stone and the house, which would be unit of space.

That takes care of the math problem, and the size of those "units" in terms of millimeters (or inches, or whatever) is not needed to solve the math problem.
However, that size makes me worried about that elderly neighbor.
If one unit is 500mm, which is 0.5 meters, the space between stones will be 1 meter, and that is way too wide a gap for an elderly lady to jump over.
Even 500mm=0.5m is an almost uncomfortably long step for me.
(My height is about average and I am not young, but I am still agile enough to chase grandchildren).
If I had to walk to a bird feeder, over rain-slick stones, I would like them even closer than 0.5m.
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