SOLUTION: an=9n, starting with n=1

Algebra.Com
Question 704503: an=9n, starting with n=1
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
an=9n starting with n = 1 generates the sequence

9, 18, 27, 36, 45, 54, ...

basically the multiples of 9

----------------------------------------------------------------
an = 9^n starting with n = 1 generates the sequence

9, 81, 729, 6561, ...

which are the powers of 9

--------------------------------------------------------------------------------------------------------------

If you need more help, you can email me at jim_thompson5910@hotmail.com

To find other ways to contact me, you can also visit my website: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim

--------------------------------------------------------------------------------------------------------------

RELATED QUESTIONS

Starting with n=1, find the first 5 terms of: {{{ an=(7n!)/(n+2) }}}. Please explain... (answered by MathLover1)
I need help with... (answered by rfer)
Can you please help with this question 2(9n-1) + 7(n+6) =... (answered by stanbon)
I need to justify each of these step, please help me with this. 5(n+4)+9n= (5n+20)+9n (answered by funmath)
Consider a sequence given by the formula f(n) = 1/3n-1 starting with n = 1. Generate the... (answered by fractalier)
2/3{9n-6}=4{n+1} (answered by askmemath)
2(9n-1)+7(n+6)=-60 (answered by vleith)
2(9n-1)+7(n+6)=-60 (answered by jim_thompson5910)
n-10+9n-3 (answered by jim_thompson5910)