Hi,
the idea is too check to see if:
1) the probabilites in @ case total 1
2) there is no negative probabilities listed as an option
A 1/5 + 5/12 + 1/3 + 1/6 = 12/60 + 25/60 + 20/60 + 10/60 = 67/60 ≠ 1
B 0.2 + 2/5 + 0.3 = 2/10 + 4/10 + 3/10 = 9/10 ≠ 1
C P(x)is -0.1 not possible... cannot have a 'negative' probability
Determine whether each of the distributions given below represents a probability...(answered by Edwin McCravy)