SOLUTION: find asub 1 for each geometric series described 1. Ssubn= 45/8 r=1/2 n=4 2. Subn=-242 r=3 n=5

Algebra.Com
Question 65393: find asub 1 for each geometric series described
1. Ssubn= 45/8 r=1/2 n=4
2. Subn=-242 r=3 n=5

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
find asub 1 for each geometric series described
1. S(n)= 45/8; r=1/2 ; n=4
S(4)=a(1)[(1/2)^(4+1)-1]/[(1/2)-1]=45/8
a(1)[1/32-1]/[-1/2]=45/8
a(1)[-31/32/-1/2]=45/8
a(1)[31/16]=45/8
a(1)=90/31
---------------
2. Subn=-242 r=3 n=5
Follow the same pattern as in #1
----------
Cheers,
Stan H.

RELATED QUESTIONS

Find the sum of each geometric series described 1. asub1= 512 r=1/2 n=6 2. 3 + 6 +... (answered by venugopalramana)
Find a(1) in a geometric series for which S(n) = 189, r = 1/2, and a(n) =3.... (answered by venugopalramana)
Please help me find the sum of this finite geometric series. 2+10+50+250+1250. So far I... (answered by ptaylor)
Find the sum of a geometric series for which a(1)=1, r=2, and n=6 Thanks... (answered by fractalier)
Find a(1) in a geometric series for which S(n) =189, r=1/2, and a(n)=3. Thank... (answered by venugopalramana)
find the sum of the geometric series 6 [SUM] 2^n n=1 n=1 2^1=2 n=2 2^2=4 n=3 (answered by jim_thompson5910)
find the nth term of each geometric sequence.... (answered by stanbon)
My problem is to find the indicated term for the geometric series described : Sn=33... (answered by Theo)
For questions 1 and 2 evaluate each infinte geometric series. 1. infinity (sign) sigma... (answered by robertb)