SOLUTION: Please help me answer the following question: If y varies inversely as x and y=8 when x=4, find y when x=16

Question 6532: Please help me answer the following question: If y varies inversely as x and y=8 when x=4, find y when x=16
Found 4 solutions by Mike, GrantJones, Fombitz, Alan3354:
Answer by Mike(39)   (Show Source): You can put this solution on YOUR website!
In terms of maths we have y or converting to an equation, where k is the constant of proportionality. Now we need to find the value of k. For this we need to know y and x, which we do from the question. So put the values into the equation to find k.

So the equation is now: . You can now do the final part: "find y when x=16".

Hope that helps.
Regards,
-Mike

Answer by GrantJones(3)   (Show Source): You can put this solution on YOUR website!
You can use my pluggable solvers that would solve quadratic equations and 2x2 linear systems, do Simplification and substitution solvers, (for now) for you, and will "show work". See this example and its source. Learn more about pluggable solvers. They are great for your productivity and sanity. It saves you time and lets you concentrate on the truly interesting part of tutoring, not on solving boring repetitive problems. It also points students to interactive solvers/lessons where they can learn by themselves.
Re-use most frequently used solvers, do not reinvent the wheel. Most problems are standard! It is easy: click the button and replace the values with those from the problem that you are solving. The student, then, will see your explanation and work of the solver. Most solvers give very detailed explanations.
OK so for your equation. IDK.
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!

So,

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Please help me answer the following question: If y varies inversely as x and y=8 when x=4, find y when x=16
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y varies inversely as x --> y = k/x where k is some constant.
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y=8 when x=4 --> 8 = k/4 --> k = 32
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find y when x=16
y = 32/16
y = 2

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