SOLUTION: 1)Find the sum of the arithmetic sequence 2, 4, 6, 8, ..., 70. 2)Find the sum of the geometric sequence 42, 7, 7/6, .... , 42(1/6)^8 3)find the sum of the first n terms of t

Algebra.Com
Question 631827: 1)Find the sum of the arithmetic sequence 2, 4, 6, 8, ..., 70.
2)Find the sum of the geometric sequence 42, 7, 7/6, .... , 42(1/6)^8
3)find the sum of the first n terms of the sequence. The sequences are either arithmetic or geometric. -1, 11, -121, ...; n = 9
4)find the sum of the first n terms of the sequence. The sequences are either arithmetic or geometric. 14, 8, 2,...; n=9

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Arithmetic sequence
In General: and
{2, 4, 6, 8, ..., 70) d = 2 and n = 35
finding the Sum of the first 35 Terms:
14, 8, 2,...; n=9 d = -6
finding the Sum of the first 9 Terms:
Geometric sequence
In General: and
Find the sum of the geometric sequence 42, 7, 7/6, .... , and last term is the 9th Term
finding the Sum of the first 9 Terms: using as is so insignificant
-1, 11, -121, ...; n = 9 , r = -11 :
finding the Sum of the first 9 Terms:
will Let You finish this one out
RELATED QUESTIONS

i really need help with this! i already got on tutor.com and didnt understand how they... (answered by ewatrrr)
Hi, these questions are really confusing, could you please help me? For problems 9 and (answered by ikleyn)
Find the sum of the first 70 terms of the arithmetic sequence: 22,19,16,13 Find the... (answered by fractalier)
the sum of the first 6 terms of the geometric sequence 1, -2, 4, -8, ... is... (answered by htmentor)
decide whether the sequence is arithmetic, geometric, or neither. Explain your answer. (answered by KMST)
2/7 of 3 3/4 added 1/7 of 6 7/8 find the sum (answered by Alan3354)
1. Find the 20th term of the following sequence. -6, -4, -2, 0, ... 32 44 46 2.... (answered by ewatrrr)
Find the sum of the arithmetic sequence.... (answered by reviewermath)
write the first six terms of the sequence 2. an=(n+1)^3 4. an=n/n+3 write the next (answered by richard1234)