SOLUTION: 1.1 Given 16(x-2)^3+8(x-2)^4+4(x-2)^5+...... As a geometric sequence and x is not equal to 2 1.1.1 Calculate the value of x for which sequence converges 1.1.2 Determine the s

Question 626875: 1.1 Given 16(x-2)^3+8(x-2)^4+4(x-2)^5+...... As a geometric sequence and x is not equal to 2
1.1.1 Calculate the value of x for which sequence converges
1.1.2 Determine the sum to infinity of the series if x=2.5
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
1.1 To get the next term, multiply by . This is the common ratio, r. The first term is . The sum of the infinite geometric series is equal to

=
=
1.1.1 The geometric series is convergent iff

1.1.2 x=2.5
, substitute x = 2.5
=
=

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