Hi,

finding the sum  of sequence: 41+42+43+44+.....+118

Arithmetic Sequence with  and d = 1





     n = 118-41 + 1

     n = 78







 

Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
 Trying to find the sum 41+42+43+44+.....+118

.

Partial sum of an arithmetic sequence:

S = n((a1+an)/2)

where

S = sum of n numbers

n = 118-40 = 78

a1 = 41

an = 118

.

S = 78((41+118)/2)

S = 78(159/2)

S = 78(79.5)

s = 6201

 

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