SOLUTION: What is the sum of an arithmetic series with Sigma (n on top, k=50 on the bottom, and the equation is just k.) This should be easy but I'm just having a major brain fart today...

Question 603123: What is the sum of an arithmetic series with Sigma (n on top, k=50 on the bottom, and the equation is just k.) This should be easy but I'm just having a major brain fart today...
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
=50+51+52+ ... +(n-2)+(n-1)+n is a sum of n-49 terms.
It can also be written as:
=
There are many ways to approach the problem using "pre-cooked" formulas and results.
Otherwise, cooking from scratch,
=50+51+52+ ... +(n-2)+(n-1)+n+50+51+52+ ... +(n-2)+(n-1)+n, with 2(n-49) terms.
Pairing terms (associative property) "head to tail" (first with last, second with second last, and so on), we get the sum of n-49 pair sums (n-49 sums of two numbersin brackets)
2S=(50+n)+(51+(n-1))+(52+(n-2)+ ...=50+50+50+ ... = 50(n-49)
So, if --->

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